en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (-2,-3),(1,-9)

Solution

midpoint

(- 2, - 3), (1, - 9)

Solution

(- \frac{1}{2}, - 6)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 2, - 3), (x_{2}, y_{2}) = (1, - 9)

= (\frac{1 - 2}{2}, \frac{- 9 - 3}{2})

Refine

= (- \frac{1}{2}, - 6)

Popular Examples

inverse of f(x)=\sqrt[3]{x+9}inverse

inverse of log_{2}(n)inverse

lo g_{2} (n)

inverse of f(x)=9-9x inverse

f (x) = 9 - 9 x

asymptotes of-2(x-2)^2 asymptotes

- 2 (x - 2)^{2}

inverse of f(x)=\sqrt[5]{(3x-1)/(x-2)}inverse

Frequently Asked Questions (FAQ)

What is the midpoint (-2,-3),(1,-9) ?
The midpoint (-2,-3),(1,-9) is (-1/2 ,-6)