What is the domain of f(x)=sqrt((x^2-9)/(ln(x+1))) ?

The domain of f(x)=sqrt((x^2-9)/(ln(x+1))) is -1 = 3

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domain of f(x)=sqrt((x^2-9)/(ln(x+1)))

domain

f (x) = \frac{x ^{2} - 9}{ln ( x + 1 )}

- 1 < x < 0 or x \geq 3

Interval Notation

(- 1, 0) \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

- 1 < x < 0 or x \geq 3

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 < x < 0 or x \geq 3

f (x) = 2^{x} - 7

\frac{4 x ^{2} - 16 x + 17}{x ^{2} - 4 x + 4}

y - 3 = - 3 (x - 1)

f (x) = - 4 x

What is the domain of f(x)=sqrt((x^2-9)/(ln(x+1))) ?
The domain of f(x)=sqrt((x^2-9)/(ln(x+1))) is -1<x<0\lor x>= 3