What is the domain of \sqrt[4]{8+x}+log_{10}(x^2) ?

The domain of \sqrt[4]{8+x}+log_{10}(x^2) is -8 0

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domain of \sqrt[4]{8+x}+log_{10}(x^2)

domain

- 8 \leq x < 0 or x > 0

Interval Notation

[- 8, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find positive values for logs:

x < 0 or x > 0

Combine real regions and undefined points for final function domain

- 8 \leq x < 0 or x > 0

f (x) = - 4 x

f (x) = 2^{x + 1}

(0, 5), (5, 0)

f (x) = 3 x^{4} - 4 x^{3} + 2

f (x) = \frac{- 5 + 5 x}{2 - 3 x}

What is the domain of \sqrt[4]{8+x}+log_{10}(x^2) ?
The domain of \sqrt[4]{8+x}+log_{10}(x^2) is -8<= x<0\lor x>0