What is the domain of (1/(sqrt(4)))^2-4 ?

The domain of (1/(sqrt(4)))^2-4 is -infinity <x<infinity

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domain of (1/(sqrt(4)))^2-4

domain

(\frac{1}{4})^{2} - 4

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x}{x ^{2} - 25}

y = 2 x

f (x) = 2 x^{3} - 4

\frac{x ^{2} + x + 1}{x}

f (x) = \frac{x - 4}{x ^{2} + 8 x + 16}

What is the domain of (1/(sqrt(4)))^2-4 ?
The domain of (1/(sqrt(4)))^2-4 is -infinity <x<infinity