What is the domain of-9/(2t^{3/2)} ?

The domain of-9/(2t^{3/2)} is t>0

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domain of-9/(2t^{3/2)}

domain

- \frac{9}{2 t ^{\frac{3}{2}}}

t > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 0

Find undefined (singularity) points:

t = 0

Combine real regions and undefined points for final function domain

t > 0

f (x) = x^{3} - 12 x

f (x) = - x - 3

f (x) = x^{2} + 2 x + 1

f (x) = \frac{( 5 x - 3 )}{2 x + 5}

\frac{( x - 4 ) ^{2}}{x + 2}