What is the domain of f(x)=(sqrt(6+x))/(8-x) ?

The domain of f(x)=(sqrt(6+x))/(8-x) is -6 8

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domain of f(x)=(sqrt(6+x))/(8-x)

domain

f (x) = \frac{6 + x}{8 - x}

- 6 \leq x < 8 or x > 8

Interval Notation

[- 6, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

- 6 \leq x < 8 or x > 8

x + y = - 3

x^{2} - 2 x - 15

x^{2} - 3 x + 3

y = \frac{3}{5} x - 7

What is the domain of f(x)=(sqrt(6+x))/(8-x) ?
The domain of f(x)=(sqrt(6+x))/(8-x) is -6<= x<8\lor x>8