What is the domain of h(x)= 1/(x-3) ?

The domain of h(x)= 1/(x-3) is x 3

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domain of h(x)= 1/(x-3)

domain

h (x) = \frac{1}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = sin (\frac{7 π}{2})

(\frac{5}{2})^{x}

\frac{5 x}{9 x - 1}

f (x) = \frac{x}{x ^{2} - 4}

f (x) = \frac{ln ( x ) + 1}{ln ( x ) - 1}

What is the domain of h(x)= 1/(x-3) ?
The domain of h(x)= 1/(x-3) is x<3\lor x>3