What is the domain of f(x)=(sqrt(x+1))/(x-4) ?

The domain of f(x)=(sqrt(x+1))/(x-4) is -1 4

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domain of f(x)=(sqrt(x+1))/(x-4)

domain

f (x) = \frac{x + 1}{x - 4}

- 1 \leq x < 4 or x > 4

Interval Notation

[- 1, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

- 1 \leq x < 4 or x > 4

f (x) = \frac{x ^{3}}{x ^{2} - 1}

\frac{1}{x ^{2} + 1}

f (x) = 6 x^{2} + 4

f (x) = x^{2} - 2

What is the domain of f(x)=(sqrt(x+1))/(x-4) ?
The domain of f(x)=(sqrt(x+1))/(x-4) is -1<= x<4\lor x>4