What is the domain of f(x)=sqrt(x-1)+1 ?

The domain of f(x)=sqrt(x-1)+1 is x>= 1

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domain of f(x)=sqrt(x-1)+1

domain

f (x) = x - 1 + 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

2 x + 3 y = 5

f (x) = \frac{( x + 1 )}{x - 4}

x - 2 y = 4

f (x) = (20 - x)^{\frac{1}{4}}

\frac{- 2 e ^{t}}{1 - 2 e ^{t}}

What is the domain of f(x)=sqrt(x-1)+1 ?
The domain of f(x)=sqrt(x-1)+1 is x>= 1