What is the domain of f(x)=sqrt(x^3-x^2-6x) ?

The domain of f(x)=sqrt(x^3-x^2-6x) is -2 = 3

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domain of f(x)=sqrt(x^3-x^2-6x)

domain

f (x) = x^{3} - x^{2} - 6 x

- 2 \leq x \leq 0 or x \geq 3

Interval Notation

[- 2, 0] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 0 or x \geq 3

The function domain

- 2 \leq x \leq 0 or x \geq 3

(x^{2} - 2)^{3}

y = - \frac{3}{4} x - 2

f (x) = - \frac{5}{4} x

f (x) = \frac{9}{x} + 12

4 x - 3 y = 12

What is the domain of f(x)=sqrt(x^3-x^2-6x) ?
The domain of f(x)=sqrt(x^3-x^2-6x) is -2<= x<= 0\lor x>= 3