inflection (x^2-9)e^x

Lösung

wendepunkte

(x^{2} - 9) e^{x}

(- 2 - 11, e^{- 2 - 11} (6 + 411)), (- 2 + 11, e^{- 2 + 11} (6 - 411))

Schritte zur Lösung

f^{''} (x) = e^{x} (x^{2} + 4 x - 7)

Intervalle finden:

Konkav steigend

: - \infty < x < - 11 - 2,

Konkav fallend

: - 11 - 2 < x < - 2 + 11,

Konkav steigend

: - 2 + 11 < x < \infty

Stecke

x = - 2 - 11

(x^{2} - 9) e^{x} : e^{- 2 - 11} (6 + 411)

(- 2 - 11, e^{- 2 - 11} (6 + 411))

Stecke

x = - 2 + 11

(x^{2} - 9) e^{x} : e^{- 2 + 11} (6 - 411)

(- 2 + 11, e^{- 2 + 11} (6 - 411))

(- 2 - 11, e^{- 2 - 11} (6 + 411)), (- 2 + 11, e^{- 2 + 11} (6 - 411))

d o main \frac{3}{3 + x}

in v erse f (x) = \frac{x}{3} + 2

d o main f (x) = \frac{4 x + 8}{x ^{2} - 4}

a sy m pt o t es 3 x^{2} - x^{3}

in v erse f (x) = arcsin (x)