What is the domain of y=sqrt(ln(x^2-8x)) ?

The domain of y=sqrt(ln(x^2-8x)) is x = sqrt(17)+4

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domain of y=sqrt(ln(x^2-8x))

domain

y = ln (x^{2} - 8 x)

x \leq - 17 + 4 or x \geq 17 + 4

Interval Notation

(- \infty, - 17 + 4] \cup [17 + 4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 17 + 4 or x \geq 17 + 4

The function domain

x \leq - 17 + 4 or x \geq 17 + 4

y = 10 x^{2} - 4

f (x) = \frac{x - 5}{10 x}

x^{2} - 1

f (x) = x^{2} - 4 x

y = - 2 x - 2

What is the domain of y=sqrt(ln(x^2-8x)) ?
The domain of y=sqrt(ln(x^2-8x)) is x<=-sqrt(17)+4\lor x>= sqrt(17)+4