What is the domain of g(x)=sqrt(x^2-6x-27) ?

The domain of g(x)=sqrt(x^2-6x-27) is x = 9

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domain of g(x)=sqrt(x^2-6x-27)

domain

g (x) = x^{2} - 6 x - 27

x \leq - 3 or x \geq 9

Interval Notation

(- \infty, - 3] \cup [9, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 9

The function domain

x \leq - 3 or x \geq 9

f (x) = 15.5 - 5 t

f (x) = x^{3} - 9 x^{2} - x + 9

- 4 x^{4} + 5 x^{3} - x^{2}

5 x^{3} - 5 x^{2} - 4

f (x) = 8 x

What is the domain of g(x)=sqrt(x^2-6x-27) ?
The domain of g(x)=sqrt(x^2-6x-27) is x<=-3\lor x>= 9