What is the domain of f(x)=(2x^2-6x+2)/((2x-3)^2) ?

The domain of f(x)=(2x^2-6x+2)/((2x-3)^2) is x 3/2

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domain of f(x)=(2x^2-6x+2)/((2x-3)^2)

domain

f (x) = \frac{2 x ^{2} - 6 x + 2}{( 2 x - 3 ) ^{2}}

x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}

The function domain

x < \frac{3}{2} or x > \frac{3}{2}

f (x) = x^{4} - 54 x^{2} + 1

f (x) = - 2 sin (2 π x)

f (x) = - 2 - x^{\frac{2}{3}}

y = - \frac{1}{2} x + 3

f (x) = 4 - x + 3

What is the domain of f(x)=(2x^2-6x+2)/((2x-3)^2) ?
The domain of f(x)=(2x^2-6x+2)/((2x-3)^2) is x< 3/2 \lor x> 3/2