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受欢迎的函数 >

inflection f(x)=e^{-2x}-x^2

解答

拐点

f (x) = e^{- 2 x} - x^{2}

解答

(\frac{ln ( 2 )}{2}, \frac{1}{2} - \frac{ln ^{2} ( 2 )}{4})

求解步骤

f^{''} (x) = 4 e^{- 2 x} - 2

Find intervals:

向上凹

: - \infty < x < \frac{ln ( 2 )}{2},

向下凹

: \frac{ln ( 2 )}{2} < x < \infty

将

x = \frac{ln ( 2 )}{2}

代入

e^{- 2 x} - x^{2} : \frac{1}{2} - \frac{ln ^{2} ( 2 )}{4}

(\frac{ln ( 2 )}{2}, \frac{1}{2} - \frac{ln ^{2} ( 2 )}{4})

作图

流行的例子

截距 (x^3)/(2x^2-8)

in t erce pt s \frac{x ^{3}}{2 x ^{2} - 8}

inflection f(x)=3x^4-18x^3+x-7

in f l ec t i o n f (x) = 3 x^{4} - 18 x^{3} + x - 7

r an g e f (x) = 2

求反函数 f(x)=2(x-3)^2+4

in v erse f (x) = 2 (x - 3)^{2} + 4

定义域 f(x)=sqrt(-x)-4

d o main f (x) = - x - 4