What is the domain of f(x)=sqrt(x^2-3x-4) ?

The domain of f(x)=sqrt(x^2-3x-4) is x = 4

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domain of f(x)=sqrt(x^2-3x-4)

domain

f (x) = x^{2} - 3 x - 4

x \leq - 1 or x \geq 4

Interval Notation

(- \infty, - 1] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 4

The function domain

x \leq - 1 or x \geq 4

y = 4 x - 1

f (x) = 2 x

6 x^{3} + 1

f (x) = (x - 2)^{2}

3 cos (x) - 1

What is the domain of f(x)=sqrt(x^2-3x-4) ?
The domain of f(x)=sqrt(x^2-3x-4) is x<=-1\lor x>= 4