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Popular >

range of f(x)=x^2-4x-12

Solution

range

f (x) = x^{2} - 4 x - 12

Solution

f (x) \geq - 16

+1

Interval Notation

[- 16, \infty)

Solution steps

Vertex of

x^{2} - 4 x - 12 :

Minimum

(2, - 16)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (2, - 16)

f (x) \geq - 16

Popular Examples

symmetry y=-x^2+16x-94 symmetry

y = - x^{2} + 16 x - 94

domain of f(x)=sqrt(8x)domain

f (x) = 8 x

asymptotes of f(x)=(2x+3)/(x+2)asymptotes

f (x) = \frac{2 x + 3}{x + 2}

extreme f(x)=e^{1/x}*(x+2)extreme points

f (x) = e^{\frac{1}{x}} \cdot (x + 2)

intercepts of f(x)=x^2-100sqrt(x)+6 intercepts

f (x) = x^{2} - 100 x + 6

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2-4x-12 ?
The range of f(x)=x^2-4x-12 is f(x)>=-16