What is the domain of f(x)= 1/(1-x^2) ?

The domain of f(x)= 1/(1-x^2) is x 1

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domain of f(x)= 1/(1-x^2)

domain

f (x) = \frac{1}{1 - x ^{2}}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = 1 - \frac{1}{x}

f (x) = 2 cos (\frac{3 x}{2})

(- 1, 0), (7, 3)

- x^{2} + 3

f (x) = x + 6 + 3

What is the domain of f(x)= 1/(1-x^2) ?
The domain of f(x)= 1/(1-x^2) is x<-1\lor-1<x<1\lor x>1