What is the domain of f(x)= 1/(sqrt(2x-46)) ?

The domain of f(x)= 1/(sqrt(2x-46)) is x>23

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domain of f(x)= 1/(sqrt(2x-46))

domain

f (x) = \frac{1}{2 x - 46}

x > 23

Interval Notation

(23, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 23

Find undefined (singularity) points:

x = 23

Combine real regions and undefined points for final function domain

x > 23

f (x) = 12 x + 7

(- 2, - 6), (3, 14)

y = \frac{1}{x}

(- 1, 1.8), (1, - 2.2)

f (x) = \frac{x + 8}{5 x + 2}

What is the domain of f(x)= 1/(sqrt(2x-46)) ?
The domain of f(x)= 1/(sqrt(2x-46)) is x>23