What is the range of cos^2(t) ?

The range of cos^2(t) is 0<= f(t)<= 1

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range of cos^2(t)

range

cos^{2} (t)

0 \leq f (t) \leq 1

Interval Notation

[0, 1]

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

cos^{2} (t) : - \infty < t < \infty

Extreme Points of

cos^{2} (t) :

Maximum

(πn, 1),

Minimum

(\frac{π}{2} + πn, 0)

Find the range for the interval

- \infty < t < \infty : 0 \leq f (t) \leq 1

Combine the ranges of all domain intervals to obtain the function range

0 \leq f (t) \leq 1

- 2 x + 5 y = 10

x \to \infty lim (\frac{1}{r ^{x}})

f (x) = x^{2} - 4 x + 19

f (x) = \frac{1}{5} x + \frac{3}{10} y = 2

(- 4, 9), (- 2, 4)