What is the domain of f(x)=sqrt(6-x-x^2) ?

The domain of f(x)=sqrt(6-x-x^2) is -3<= x<= 2

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domain of f(x)=sqrt(6-x-x^2)

domain

f (x) = 6 - x - x^{2}

- 3 \leq x \leq 2

Interval Notation

[- 3, 2]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 2

The function domain

- 3 \leq x \leq 2

(x + 6) (x - 1)^{2}

f (x) = - \frac{3}{∣ x + 2 ∣}

f (x) = - \frac{1}{x ^{4}} - 3

\frac{5 x - 3}{2 x + 1}

f (x) = \frac{3 x - 6}{- x ^{2} - 2 x + 8}

What is the domain of f(x)=sqrt(6-x-x^2) ?
The domain of f(x)=sqrt(6-x-x^2) is -3<= x<= 2