What is the range of-3sin(pi/2 x)+1 ?

The range of-3sin(pi/2 x)+1 is -2<= f(x)<= 4

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range of-3sin(pi/2 x)+1

range

- 3 sin (\frac{π}{2} x) + 1

- 2 \leq f (x) \leq 4

Interval Notation

[- 2, 4]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (\frac{π}{2} x) \leq 1

- 1 \leq sin (\frac{π}{2} x) \leq 1

Multiply the edges of the range by:

- 3

- 3 \leq - 3 sin (\frac{π}{2} x) \leq 3

Add to the edges of the range:

1

- 2 \leq - 3 sin (\frac{π}{2} x) + 1 \leq 4

Therefore the range is

- 2 \leq f (x) \leq 4

(6.4) (2.8)

f (x) = 5 x^{4} - 6 x^{3}

x^{2} + 4 x - 3

7 x - 5

y = \frac{2 x + 3}{x ( x + 1 )}

What is the range of-3sin(pi/2 x)+1 ?
The range of-3sin(pi/2 x)+1 is -2<= f(x)<= 4