What is the domain of y=(x-8)(sqrt(x+2)) ?

The domain of y=(x-8)(sqrt(x+2)) is x>=-2

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domain of y=(x-8)(sqrt(x+2))

domain

y = (x - 8) (x + 2)

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

f (x) = 7 - 2 (x - 1)^{2}

y = \frac{x + 1}{x ^{2} - 4}

y = x + 5

g (x) = x^{2} - 9

f (x) = \frac{x - 2}{x ^{2} - 4}

What is the domain of y=(x-8)(sqrt(x+2)) ?
The domain of y=(x-8)(sqrt(x+2)) is x>=-2