What is the domain of f(x)=(sqrt(t-5))/(3t-18) ?

The domain of f(x)=(sqrt(t-5))/(3t-18) is 5 6

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domain of f(x)=(sqrt(t-5))/(3t-18)

domain

f (x) = \frac{t - 5}{3 t - 18}

5 \leq t < 6 or t > 6

Interval Notation

[5, 6) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 5

Find undefined (singularity) points:

t = 6

Combine real regions and undefined points for final function domain

5 \leq t < 6 or t > 6

f (x) = x + 3 - \frac{1}{x}

f (x) = 4 x^{3} - x^{4}

\frac{x ^{2}}{x ^{2} - 1}

f (x) = \frac{2 x ^{2} - 7 x + 2}{x - 4}

f (x) = x^{\frac{6}{5}} - 12 x^{\frac{1}{5}}

What is the domain of f(x)=(sqrt(t-5))/(3t-18) ?
The domain of f(x)=(sqrt(t-5))/(3t-18) is 5<= t<6\lor t>6