144x^2+144y^2-96x+72y-11=0

解

144 x^{2} + 144 y^{2} - 96 x + 72 y - 11 = 0

(a, b) = (\frac{1}{3}, - \frac{1}{4}), r = \frac{1}{2}

解答ステップ

144 x^{2} + 144 y^{2} - 96 x + 72 y - 11 = 0

144 x^{2} + 144 y^{2} - 96 x + 72 y - 11 = 0

を標準的な円のequationの形式で書き換える

(x - \frac{1}{3})^{2} + (y - (- \frac{1}{4}))^{2} = (\frac{1}{2})^{2}

ゆえに円の特性は:

(a, b) = (\frac{1}{3}, - \frac{1}{4}), r = \frac{1}{2}