de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

4x^2+4y^2+40-32y-5=0

Lösung

4 x^{2} + 4 y^{2} + 40 - 32 y - 5 = 0

Lösung

(a, b) = (0, 4), r = \frac{29}{2}

Schritte zur Lösung

4 x^{2} + 4 y^{2} + 40 - 32 y - 5 = 0

Rewrite

4 x^{2} + 4 y^{2} + 40 - 32 y - 5 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = (\frac{29}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = \frac{29}{2}

Graph

Beliebte Beispiele

2x^{(2)}+2y^{(2)}+10x-2y-7=0

2 x^{(2)} + 2 y^{(2)} + 10 x - 2 y - 7 = 0

x^2+4x+y^2-3y=0

x^{2} + 4 x + y^{2} - 3 y = 0

x^2+y^2-4y-15=45

x^{2} + y^{2} - 4 y - 15 = 45

x^2+y^2-4x+6y-23=0

x^{2} + y^{2} - 4 x + 6 y - 23 = 0

y^2=8x-2-13-x^2

y^{2} = 8 x - 2 - 13 - x^{2}