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Beliebt Geometry >

4(x^2-2x+1)+4(y^2-y+0)=11+1+0

Lösung

4 (x^{2} - 2 x + 1) + 4 (y^{2} - y + 0) = 11 + 1 + 0

Lösung

(a, b) = (1, \frac{1}{2}), r = \frac{13}{2}

Schritte zur Lösung

4 (x^{2} - 2 x + 1) + 4 (y^{2} - y + 0) = 11 + 1 + 0

Rewrite

4 (x^{2} - 2 x + 1) + 4 (y^{2} - y + 0) = 11 + 1 + 0

in the form of the standard circle equation

(x - 1)^{2} + (y - \frac{1}{2})^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (1, \frac{1}{2}), r = \frac{13}{2}

Graph

Beliebte Beispiele

x^2+y^2-10x+12y-83-0=0

x^{2} + y^{2} - 10 x + 12 y - 83 - 0 = 0

x^2+y^2-8x-14y-7=0

x^{2} + y^{2} - 8 x - 14 y - 7 = 0

4x^2+4y^2+40x+56y+100=0

4 x^{2} + 4 y^{2} + 40 x + 56 y + 100 = 0

0=1-13(x^2+y^2)

0 = 1 - 13 (x^{2} + y^{2})

x^{2} + y^{2} - 6 y = - 8