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Beliebt Geometry >

x^2+y^2-2x>= 0

Lösung

x^{2} + y^{2} - 2 x \geq 0

Lösung

(a, b) = (1, 0), r = 1

Schritte zur Lösung

x^{2} + y^{2} - 2 x \geq 0

Rewrite

x^{2} + y^{2} - 2 x \geq 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 1

Graph

Beliebte Beispiele

x^2+6x+y^2+2y-3=0

x^{2} + 6 x + y^{2} + 2 y - 3 = 0

25x^2+25y^2+60y-20x-360=0

25 x^{2} + 25 y^{2} + 60 y - 20 x - 360 = 0

(x+5)^2+(y+3)^2=100

(x + 5)^{2} + (y + 3)^{2} = 100

4x^2+4y^2-8x+16y+4=0

4 x^{2} + 4 y^{2} - 8 x + 16 y + 4 = 0

x^2+y^2+2(29/22)x+2(29/22)y+(-142/11)=0

x^{2} + y^{2} + 2 (\frac{29}{22}) x + 2 (\frac{29}{22}) y + (- \frac{142}{11}) = 0