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Beliebt Geometry >

center x^2+y^2+6x-4y-5=0

Lösung

center

x^{2} + y^{2} + 6 x - 4 y - 5 = 0

Lösung

(- 3, 2)

Schritte zur Lösung

x^{2} + y^{2} + 6 x - 4 y - 5 = 0

Rewrite

x^{2} + y^{2} + 6 x - 4 y - 5 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 2)^{2} = (32)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 2), r = 32

And the center is:

(- 3, 2)

Graph

Beliebte Beispiele

center (x+2)^2+(y+3)^2=81

ce n t er (x + 2)^{2} + (y + 3)^{2} = 81

center 3x^2+3y^2-18x+6y+2=0

ce n t er 3 x^{2} + 3 y^{2} - 18 x + 6 y + 2 = 0

center (x-13)^2+(y+12)^2=64

ce n t er (x - 13)^{2} + (y + 12)^{2} = 64

center x^2+y^2-2/3 x-5/3 y-5/9 =0

ce n t er x^{2} + y^{2} - \frac{2}{3} x - \frac{5}{3} y - \frac{5}{9} = 0

center ((x+2)^2)/(16)+((y+5)^2)/(16)=1

ce n t er \frac{( x + 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1