6x^2+12x+y+13=0

Lösung

6 x^{2} + 12 x + y + 13 = 0

(h, k) = (- 1, - 7), p = - \frac{1}{24}

Schritte zur Lösung

6 x^{2} + 12 x + y + 13 = 0

Rewrite

6 x^{2} + 12 x + y + 13 = 0

in the standard form

4 (- \frac{1}{24}) (y - (- 7)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 7), p = - \frac{1}{24}

y + x^{2} = 6

y + x^{2} = 0

4^{2} = 2 y + x^{2}

2 y^{2} + 8 y + x + 1 = 0

y \geq x^{2} - 9