2x^2-7x+k(x)=0

Lösung

2 x^{2} - 7 x + k (x) = 0

(h, k) = (\frac{7}{4}, \frac{49}{8}), p = - \frac{1}{8}

Schritte zur Lösung

2 x^{2} - 7 x + y = 0

Rewrite

2 x^{2} - 7 x + y = 0

in the standard form

4 (- \frac{1}{8}) (y - \frac{49}{8}) = (x - \frac{7}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{7}{4}, \frac{49}{8}), p = - \frac{1}{8}

k (x) - x^{2} = x

y = 2 x - 6 y^{2}

y + 12 x - 2 x^{2} = 16

x = 8 y^{2}

(y + 5)^{2} = - 12 (x - 1)