((x-1)^2)/5+((y-3)^2)/4 =1

Lösung

\frac{( x - 1 ) ^{2}}{5} + \frac{( y - 3 ) ^{2}}{4} = 1

(h, k) = (1, 3), a = 5, b = 2

Schritte zur Lösung

\frac{( x - 1 ) ^{2}}{5} + \frac{( y - 3 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{5} + \frac{( y - 3 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{( 5 ) ^{2}} + \frac{( y - 3 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 3), a = 5, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 3), a = 5, b = 2

\frac{( x + 1 ) ^{2}}{1} + \frac{y ^{2}}{4} = 1

9 x^{2} + y^{2} + 144 x = - 567

x^{2} + 4 y^{2} + 2 x - 12 y + 6 = 0

\frac{( x - 6 ) ^{2}}{9} + \frac{( y + 7 ) ^{2}}{25} = 1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1