de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

3x^2+4y^2-12x+16y+16=0

Lösung

3 x^{2} + 4 y^{2} - 12 x + 16 y + 16 = 0

Lösung

(h, k) = (2, - 2), a = 2, b = 3

Schritte zur Lösung

3 x^{2} + 4 y^{2} - 12 x + 16 y + 16 = 0

Rewrite

3 x^{2} + 4 y^{2} - 12 x + 16 y + 16 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{( 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 2), a = 2, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, - 2), a = 2, b = 3

Graph

Beliebte Beispiele

4(x-2)^2+(y-3)^2=1

4 (x - 2)^{2} + (y - 3)^{2} = 1

x^2-4x+16y^2+32y+4=0

x^{2} - 4 x + 16 y^{2} + 32 y + 4 = 0

9 x^{2} + 12 y^{2} = 108

(x^2)/((2.67)^2)+(y^2)/((2.85)^2)=1

\frac{x ^{2}}{( 2.67 ) ^{2}} + \frac{y ^{2}}{( 2.85 ) ^{2}} = 1

(x^2}{45}+\frac{y^2)/9 =1

\frac{x ^{2}}{45} + \frac{y ^{2}}{9} = 1