((x-5)^2)/(49)+((y+4)^2)/(81)=1

Lösung

\frac{( x - 5 ) ^{2}}{49} + \frac{( y + 4 ) ^{2}}{81} = 1

(h, k) = (5, - 4), a = 7, b = 9

Schritte zur Lösung

\frac{( x - 5 ) ^{2}}{49} + \frac{( y + 4 ) ^{2}}{81} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{49} + \frac{( y + 4 ) ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - 5 ) ^{2}}{7 ^{2}} + \frac{( y - ( - 4 ) ) ^{2}}{9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (5, - 4), a = 7, b = 9

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (5, - 4), b = 9, a = 7

- (x - 2)^{2} - y^{2} = 4

\frac{x ^{2}}{5.6 6 ^{2}} + \frac{y ^{2}}{3.5 9 ^{2}} = 1

5 x^{2} + 2 y^{2} = 2

4 x^{2} + 9 y^{2} + 16 x + 54 y + 61 = 0

4 x^{2} - 16 x + y^{2} + 2 y + 13 = 0