x^2-2x+36y+28=0

Lösung

x^{2} - 2 x + 36 y + 28 = 0

(h, k) = (1, - \frac{3}{4}), p = - 9

Schritte zur Lösung

x^{2} - 2 x + 36 y + 28 = 0

Rewrite

x^{2} - 2 x + 36 y + 28 = 0

in the standard form

4 (- 9) (y - (- \frac{3}{4})) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - \frac{3}{4}), p = - 9

(y - (- 3))^{2} = 2 (x - 1)

y + 5 x = x^{2}

x = 6 - y^{2}

x^{2} - 8 x + m (x) = 0

y + 1 = - (x - 2)^{2}