x^2+y^2+2x+6y+2=0

解答

x^{2} + y^{2} + 2 x + 6 y + 2 = 0

(a, b) = (- 1, - 3), r = 22

求解步骤

x^{2} + y^{2} + 2 x + 6 y + 2 = 0

将

x^{2} + y^{2} + 2 x + 6 y + 2 = 0

改写为圆标准方程

(x - (- 1))^{2} + (y - (- 3))^{2} = (22)^{2}

因此圆的性质是:

(a, b) = (- 1, - 3), r = 22

a sy m pt o t es \frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

x = 3 y^{2}

v er t i ces 3 y^{2} = 24 x

v er t i ces f (x) = x^{2} - 6 x

d i rec t r i x y^{2} + 12 x + 4 y - 32 = 0