(((x+5)^2)}{10}+\frac{((y+4)^2))/8 =1

Lösung

\frac{( ( x + 5 ) ^{2} )}{10} + \frac{( ( y + 4 ) ^{2} )}{8} = 1

(h, k) = (- 5, - 4), a = 10, b = 22

Schritte zur Lösung

\frac{( x + 5 ) ^{2}}{10} + \frac{( y + 4 ) ^{2}}{8} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{10} + \frac{( y + 4 ) ^{2}}{8} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 5 ) ) ^{2}}{( 10 ) ^{2}} + \frac{( y - ( - 4 ) ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 5, - 4), a = 10, b = 22

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 5, - 4), a = 10, b = 22

3 x^{2} + y^{2} = 25

2 x^{2} + 9 y^{2} - 12 x - 18 y + 9 = 0

\frac{x ^{2}}{100} + \frac{y ^{2}}{144} = 1

3 x^{2} + 2 y^{2} - 17 x = 0

x^{2} + 4 y^{2} + 10 x + 24 y + 25 = 0