((x^2)/4)+((y^2)/(16))=1

Lösung

(\frac{x ^{2}}{4}) + (\frac{y ^{2}}{16}) = 1

(h, k) = (0, 0), a = 2, b = 4

Schritte zur Lösung

\frac{x ^{2}}{4} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 2

so l v e f or x, \frac{Y ( x ) ^{2}}{4 - x ^{2}} = 1

\frac{y ^{2}}{16} = 1 - \frac{x ^{2}}{9}

4 x^{2} + 9 y^{2} + 16 x - 36 y + 16 = 0

- 16 - x^{2} - y^{2} \geq 0

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{36} = 1