((x-4)^2)/(32)+((y-3)^2)/(36)=1

Lösung

\frac{( x - 4 ) ^{2}}{32} + \frac{( y - 3 ) ^{2}}{36} = 1

(h, k) = (4, 3), a = 42, b = 6

Schritte zur Lösung

\frac{( x - 4 ) ^{2}}{32} + \frac{( y - 3 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{32} + \frac{( y - 3 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 4 ) ^{2}}{( 4 2 ) ^{2}} + \frac{( y - 3 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (4, 3), a = 42, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (4, 3), b = 6, a = 42

\frac{( x ^{2} )}{63500} + \frac{( y ^{2} )}{50900} = 1

X^{2} + 3 Y^{2} - 4 X - 23 = 0

\frac{1}{2} x^{2} + \frac{1}{8} y^{2} = \frac{1}{4}

16 x^{2} + y^{2} = 1

16 x^{2} + 4 y^{2} - 128 x - 16 y + 206 = 0