x^2+(y-5)2=16

Lösung

x^{2} + (y - 5) 2 = 16

(h, k) = (0, 13), p = - \frac{1}{2}

Schritte zur Lösung

x^{2} + (y - 5) \cdot 2 = 16

Rewrite

x^{2} + (y - 5) \cdot 2 = 16

in the standard form:

4 (- \frac{1}{2}) (y - 13) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 13), p = - \frac{1}{2}

x^{2} + 3 x + 2 m (x) - 1 = 0

yy - 3 x = 13

x = z^{2}

(x - 3)^{2} = 8 (y + 1)

4 y^{2} + 8 x = 0