3y^2=16x

Lösung

3 y^{2} = 16 x

(h, k) = (0, 0), p = \frac{4}{3}

Schritte zur Lösung

3 y^{2} = 16 x

Rewrite

3 y^{2} = 16 x

in the standard form:

4 \cdot \frac{4}{3} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{4}{3}

y^{2} + 4 y - 2 x = 0

y > x^{2} + 2 x - 3

2 (x - 1) = 3 (y - 1)^{2}

6 x = y^{2}

y^{2} - 4 y - 16 x - 44 = 0