foki (2(x-6)^2)/3+(7(y+4)^2)/4 =1

Lösung

foki

\frac{2 ( x - 6 ) ^{2}}{3} + \frac{7 ( y + 4 ) ^{2}}{4} = 1

(6 + \frac{13}{14}, - 4), (6 - \frac{13}{14}, - 4)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{2 ( x - 6 ) ^{2}}{3} + \frac{7 ( y + 4 ) ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (6, - 4), a = \frac{3}{2}, b = \frac{2}{7}

(6 + c, - 4), (6 - c, - 4)

Compute

c :

c = \frac{3}{2}^{2} - (\frac{2}{7})^{2} : \frac{13}{14}

(6 + \frac{13}{14}, - 4), (6 - \frac{13}{14}, - 4)

f oc i \frac{( x - 11 ) ^{2}}{14} + \frac{( y - 13 ) ^{2}}{81} = 1

f oc i 25 x^{2} + 4 y^{2} + 50 x - 16 y = 59

f oc i 3 x^{2} + 7 y^{2} - 21 = 0

f oc i 81 x^{2} + 16 y^{2} = 1296

f oc i 25 x^{2} + 9 y^{2} - 100 x - 90 y + 100 = 0