center 2x^2+y^2+12x-6y+26=0

Lösung

center

2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

(- 3, 3)

Schritte zur Lösung

2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

Rewrite

2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 3 ) ) ^{2}}{( \frac{1}{2} ) ^{2}} + \frac{( y - 3 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 3, 3), a = \frac{1}{2}, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 3, 3), b = 1, a = \frac{1}{2}

And the center is:

(- 3, 3)

ce n t er 25 x^{2} + 144 y^{2} = 900

ce n t er 2 x^{2} + y^{2} = 50

ce n t er \frac{( x - h ) ^{2}}{a ^{2}} + \frac{( y - k ) ^{2}}{b ^{2}} = 1

ce n t er 13 x^{2} + 49 y^{2} = 637

ce n t er 16 x^{2} + 25 y^{2} + 32 x - 384 = 0