center (x^2)/9+(y^2)/4 =1

Lösung

center

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

(0, 0)

Schritte zur Lösung

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 3, b = 2

And the center is:

(0, 0)

ce n t er 6 x^{2} + 9 y^{2} - 18 y - 45 = 0

ce n t er \frac{( x - 3 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{81} = 1

ce n t er 25 x^{2} + 4 y^{2} - 50 x + 16 y - 59 = 0

ce n t er 9 x^{2} + 16 y^{2} = 576

ce n t er \frac{( x - 10 ) ^{2}}{4} + \frac{y ^{2}}{16} = 1