center x^2+3y^2+2x-12y+10=0

Lösung

center

x^{2} + 3 y^{2} + 2 x - 12 y + 10 = 0

(- 1, 2)

Schritte zur Lösung

x^{2} + 3 y^{2} + 2 x - 12 y + 10 = 0

Rewrite

x^{2} + 3 y^{2} + 2 x - 12 y + 10 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 2 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 2), a = 3, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, 2), a = 3, b = 1

And the center is:

(- 1, 2)

ce n t er \frac{( x + 2 ) ^{2}}{81} + \frac{y ^{2}}{36} = 1

ce n t er 25 x^{2} + 16 y^{2} < 400

ce n t er 9 x^{2} + 49 y^{2} + 18 x + 294 y - 9 = 0

ce n t er \frac{( x - 3 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

ce n t er 4 x^{2} + y^{2} - 5 = 0