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Beliebt Geometry >

center ((x+2)^2)/(16)+(y^2)/(49)=1

Lösung

center

\frac{( x + 2 ) ^{2}}{16} + \frac{y ^{2}}{49} = 1

Lösung

(- 2, 0)

Schritte zur Lösung

\frac{( x + 2 ) ^{2}}{16} + \frac{y ^{2}}{49} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{16} + \frac{y ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 0), a = 4, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 0), b = 7, a = 4

And the center is:

(- 2, 0)

Graph

Beliebte Beispiele

center+4x^2+9y^2-16x+18y=11

ce n t er + 4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

center (x^2)/4+(y^2)/9 =1

ce n t er \frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

center 8x^2+2y^2+16x=1

ce n t er 8 x^{2} + 2 y^{2} + 16 x = 1

center 25x^2+16y^2+50x-64y-311=0

ce n t er 25 x^{2} + 16 y^{2} + 50 x - 64 y - 311 = 0

center 4x^2+9y^2-16x-18y-11=0

ce n t er 4 x^{2} + 9 y^{2} - 16 x - 18 y - 11 = 0