exzentrizität (x^2)/(16)+(y^2)/(12)=1

Lösung

exzentrizität

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 23

= \frac{4 ^{2} - ( 2 3 ) ^{2}}{4}

\frac{4 ^{2} - ( 2 3 ) ^{2}}{4} = \frac{1}{2}

= \frac{1}{2}

ecce n t r i c i t y x^{2} + 3 y^{2} = 1

ecce n t r i c i t y \frac{x ^{2}}{9} + \frac{y ^{2}}{16} > 1

ecce n t r i c i t y \frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

ecce n t r i c i t y \frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

ecce n t r i c i t y 81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952