exzentrizität 5x^2+10y^2=50

Lösung

exzentrizität

5 x^{2} + 10 y^{2} = 50

\frac{1}{2}

Dezimale

0.70710 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

5 x^{2} + 10 y^{2} = 50 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 5

= \frac{( 10 ) ^{2} - ( 5 ) ^{2}}{10}

\frac{( 10 ) ^{2} - ( 5 ) ^{2}}{10} = \frac{1}{2}

= \frac{1}{2}

ecce n t r i c i t y x^{2} + 4 y^{2} - 2 x - 16 y + 13 = 0

ecce n t r i c i t y \frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

ecce n t r i c i t y \frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1

ecce n t r i c i t y 10 x^{2} + 5 y^{2} = 50