exzentrizität (x^2)/(196)+(y^2)/(121)=1

Lösung

exzentrizität

\frac{x ^{2}}{196} + \frac{y ^{2}}{121} = 1

\frac{5 3}{14}

Dezimale

0.61858 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{196} + \frac{y ^{2}}{121} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 14, b = 11

= \frac{1 4 ^{2} - 1 1 ^{2}}{14}

\frac{1 4 ^{2} - 1 1 ^{2}}{14} = \frac{5 3}{14}

= \frac{5 3}{14}

ecce n t r i c i t y \frac{x ^{2}}{5} + \frac{y ^{2}}{20.98} = 1

ecce n t r i c i t y 16 x^{2} + 192 x + 576 + 25 y^{2} = 1600

ecce n t r i c i t y x^{2} + 2 y^{2} = 3

ecce n t r i c i t y 4 x^{2} + 9 y^{2} = 144

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1