achse 9x^2+25y^2=900

Lösung

achse

9 x^{2} + 25 y^{2} = 900

semi - major axis a = 10, semi - minor axis b = 6

Schritte zur Lösung

9 x^{2} + 25 y^{2} = 900

Rewrite

9 x^{2} + 25 y^{2} = 900

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 6

a x i s \frac{( x - 2 ) ^{2}}{36} + \frac{( y + 5 ) ^{2}}{9} = 1

a x i s 25 x^{2} + 9 y^{2} - 100 x + 18 y - 116 = 0

a x i s 16 x^{2} + y^{2} - 64 x + 8 y + 16 = 0

a x i s 3 x^{2} + y^{2} + 2 x - 6 y = 3

a x i s \frac{( x - 8 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{100} = 1